(5d-7)(5d-6)=25d^2+d+42

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Solution for (5d-7)(5d-6)=25d^2+d+42 equation: 



(5d-7)(5d-6)=25d^2+d+42

We move all terms to the left:

(5d-7)(5d-6)-(25d^2+d+42)=0

We get rid of parentheses

-25d^2+(5d-7)(5d-6)-d-42=0

We multiply parentheses ..

-25d^2+(+25d^2-30d-35d+42)-d-42=0

We add all the numbers together, and all the variables

-25d^2+(+25d^2-30d-35d+42)-1d-42=0

We get rid of parentheses

-25d^2+25d^2-30d-35d-1d+42-42=0

We add all the numbers together, and all the variables

-66d=0

d=0/-66

d=0

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